[dpdk-dev] [PATCH] mempool: fix search of maximum contiguous pages

Dai, Wei wei.dai at intel.com
Thu Oct 13 13:52:15 CEST 2016


> > > diff --git a/lib/librte_mempool/rte_mempool.c
> > > b/lib/librte_mempool/rte_mempool.c
> > > index 71017e1..e3e254a 100644
> > > --- a/lib/librte_mempool/rte_mempool.c
> > > +++ b/lib/librte_mempool/rte_mempool.c
> > > @@ -426,9 +426,12 @@ rte_mempool_populate_phys_tab(struct
> > > rte_mempool *mp, char *vaddr,
> > >
> > >  	for (i = 0; i < pg_num && mp->populated_size < mp->size; i += n) {
> > >
> > > +		phys_addr_t paddr_next;
> > > +		paddr_next = paddr[i] + pg_sz;
> > > +
> > >  		/* populate with the largest group of contiguous pages */
> > >  		for (n = 1; (i + n) < pg_num &&
> > > -			     paddr[i] + pg_sz == paddr[i+n]; n++)
> > > +			     paddr_next == paddr[i+n]; n++, paddr_next += pg_sz)
> > >  			;
> >
> > Good catch.
> > Why not just paddr[i + n - 1] != paddr[i + n]?
> 
> Sorry, I meant 'paddr[i + n - 1] + pg_sz == paddr[i+n]' off course.
> 
> > Then you don't need extra variable (paddr_next) here.
> > Konstantin

Thank you, Konstantin
'paddr[i + n - 1] + pg_sz = paddr[i + n]' also can fix it and have straight meaning. 
But I assume that my revision with paddr_next += pg_sz may have a bit better performance.
By the way, paddr[i] + n * pg_sz = paddr[i + n] can also resolve it.

/Wei

> >
> > >
> > >  		ret = rte_mempool_populate_phys(mp, vaddr + i * pg_sz,
> > > --
> > > 2.7.4



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