[dpdk-dev] [PATCH] ring: guarantee ordering of cons/prod loading when doing enqueue/dequeue
Kuusisaari, Juhamatti
Juhamatti.Kuusisaari at coriant.com
Mon Oct 23 11:05:24 CEST 2017
Hi,
> On 10/20/2017 1:43 PM, Jerin Jacob Wrote:
> > -----Original Message-----
> >>
> [...]
> >> dependant on each other.
> >> Thus a memory barrier is neccessary.
> > Yes. The barrier is necessary.
> > In fact, upstream freebsd fixed this issue for arm64. DPDK ring
> > implementation is derived from freebsd's buf_ring.h.
> >
> https://github.com/freebsd/freebsd/blob/master/sys/sys/buf_ring.h#L166
> >
> > I think, the only outstanding issue is, how to reduce the performance
> > impact for arm64. I believe using accurate/release semantics instead
> > of rte_smp_rmb() will reduce the performance overhead like similar
> > ring implementations below,
> > freebsd:
> >
> https://github.com/freebsd/freebsd/blob/master/sys/sys/buf_ring.h#L166
> > odp:
> > https://github.com/Linaro/odp/blob/master/platform/linux-generic/pktio
> > /ring.c
> >
> > Jia,
> > 1) Can you verify the use of accurate/release semantics fixes the
> > problem in your platform? like use of atomic_load_acq* in the reference
> code.
> > 2) If so, What is the overhead between accurate/release and plane
> > smp_smb() barriers. Based on that we need decide what path to take.
> I've tested 3 cases. The new 3rd case is to use the load_acquire barrier (half
> barrier) you mentioned at above link.
> The patch seems like:
> @@ -408,8 +466,8 @@ __rte_ring_move_prod_head(struct rte_ring *r, int
> is_sp,
> /* Reset n to the initial burst count */
> n = max;
>
> - *old_head = r->prod.head;
> - const uint32_t cons_tail = r->cons.tail;
> + *old_head = atomic_load_acq_32(&r->prod.head);
> + const uint32_t cons_tail =
> atomic_load_acq_32(&r->cons.tail);
>
> @@ -516,14 +576,15 @@ __rte_ring_move_cons_head(struct rte_ring *r, int
> is_s
> /* Restore n as it may change every loop */
> n = max;
>
> - *old_head = r->cons.head;
> - const uint32_t prod_tail = r->prod.tail;
> + *old_head = atomic_load_acq_32(&r->cons.head);
> + const uint32_t prod_tail = atomic_load_acq_32(&r->prod.tail)
> /* The subtraction is done between two unsigned 32bits
> value
> * (the result is always modulo 32 bits even if we have
> * cons_head > prod_tail). So 'entries' is always between 0
> * and size(ring)-1. */
>
> The half barrier patch passed the fuctional test.
>
> As for the performance comparision on *arm64*(the debug patch is at
> http://dpdk.org/ml/archives/dev/2017-October/079012.html), please see
> the test results
> below:
>
> [case 1] old codes, no barrier
> ============================================
> Performance counter stats for './test --no-huge -l 1-10':
>
> 689275.001200 task-clock (msec) # 9.771 CPUs utilized
> 6223 context-switches # 0.009 K/sec
> 10 cpu-migrations # 0.000 K/sec
> 653 page-faults # 0.001 K/sec
> 1721190914583 cycles # 2.497 GHz
> 3363238266430 instructions # 1.95 insn per
> cycle
> <not supported> branches
> 27804740 branch-misses # 0.00% of all
> branches
>
> 70.540618825 seconds time elapsed
>
> [case 2] full barrier with rte_smp_rmb()
> ============================================
> Performance counter stats for './test --no-huge -l 1-10':
>
> 582557.895850 task-clock (msec) # 9.752 CPUs utilized
> 5242 context-switches # 0.009 K/sec
> 10 cpu-migrations # 0.000 K/sec
> 665 page-faults # 0.001 K/sec
> 1454360730055 cycles # 2.497 GHz
> 587197839907 instructions # 0.40 insn per
> cycle
> <not supported> branches
> 27799687 branch-misses # 0.00% of all
> branches
>
> 59.735582356 seconds time elapse
>
> [case 1] half barrier with load_acquire
> ============================================
> Performance counter stats for './test --no-huge -l 1-10':
>
> 660758.877050 task-clock (msec) # 9.764 CPUs utilized
> 5982 context-switches # 0.009 K/sec
> 11 cpu-migrations # 0.000 K/sec
> 657 page-faults # 0.001 K/sec
> 1649875318044 cycles # 2.497 GHz
> 591583257765 instructions # 0.36 insn per
> cycle
> <not supported> branches
> 27994903 branch-misses # 0.00% of all
> branches
>
> 67.672855107 seconds time elapsed
>
> Please see the context-switches in the perf results
> test result sorted by time is:
> full barrier < half barrier < no barrier
>
> AFAICT, in this case ,the cpu reordering will add the possibility for
> context switching and
> increase the running time.
>
> Any ideas?
You could also try a case where you rearrange the rte_ring structure so that prod.head and cons.tail are parts of an union of a 64-bit variable and then read this 64-bit variable with one atomic read. I do not think that half barrier is even needed here with this approach, as long as you can really read the 64-bit variable fully at once. This should speed up.
Cheers,
--
Juhamatti
> Cheers,
> Jia
>
> >
> > Note:
> > This issue wont come in all the arm64 implementation. it comes on arm64
> > implementation with OOO(out of order) implementations.
> >
> >
> >> Cheers,
> >> Jia
> >>
> >>> Konstantin
> >>>
> >>>>> . In another
> >>>>> mail of this thread, we've made a simple test based on this and
> captured
> >>>>> some information and I pasted there.(I pasted the patch there :-))
> >>>> Are you talking about that one:
> >>>> http://dpdk.org/dev/patchwork/patch/30405/
> >>>> ?
> >>>> It still uses test/test/test_mbuf.c...,
> >>>> but anyway I don't really understand how mbuf_autotest supposed
> >>>> to work with these changes:
> >>>> @@ -730,7 +739,7 @@ test_refcnt_iter(unsigned int lcore, unsigned int
> iter,
> >>>> rte_ring_enqueue(refcnt_mbuf_ring, m);
> >>>> }
> >>>> }
> >>>> - rte_pktmbuf_free(m);
> >>>> + // rte_pktmbuf_free(m);
> >>>> }
> >>>> @@ -741,6 +750,12 @@ test_refcnt_iter(unsigned int lcore, unsigned
> int iter,
> >>>> while (!rte_ring_empty(refcnt_mbuf_ring))
> >>>> ;
> >>>>
> >>>> + if (NULL != m) {
> >>>> + if (1 != rte_mbuf_refcnt_read(m))
> >>>> + printf("m ref is %u\n", rte_mbuf_refcnt_read(m));
> >>>> + rte_pktmbuf_free(m);
> >>>> + }
> >>>> +
> >>>> /* check that all mbufs are back into mempool by now */
> >>>> for (wn = 0; wn != REFCNT_MAX_TIMEOUT; wn++) {
> >>>> if ((i = rte_mempool_avail_count(refcnt_pool)) == n) {
> >>>>
> >>>> That means all your mbufs (except the last one) will still be allocated.
> >>>> So the test would fail - as it should, I think.
> >>>>
> >>>>> And
> >>>>> it seems that Juhamatti & Jacod found some reverting action several
> >>>>> months ago.
> >>>> Didn't get that one either.
> >>>> Konstantin
>
> --
> Cheers,
> Jia
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