[v6] ip_frag: remove padding length of fragment

Message ID 1608125790-26496-1-git-send-email-luyicai@huawei.com (mailing list archive)
State Accepted, archived
Delegated to: Thomas Monjalon
Headers
Series [v6] ip_frag: remove padding length of fragment |

Checks

Context Check Description
ci/checkpatch success coding style OK
ci/Intel-compilation success Compilation OK
ci/iol-broadcom-Functional success Functional Testing PASS
ci/iol-broadcom-Performance success Performance Testing PASS
ci/iol-testing success Testing PASS
ci/iol-intel-Functional success Functional Testing PASS
ci/iol-intel-Performance success Performance Testing PASS

Commit Message

Yicai Lu Dec. 16, 2020, 1:36 p.m. UTC
  In some situations, we would get several ip fragments, which total
data length is less than min_ip_len(64) and padding with zeros.
We simulated intermediate fragments by modifying the MTU.
To illustrate the problem, we simplify the packet format and
ignore the impact of the packet header.In namespace2,
a packet whose data length is 1520 is sent.
When the packet passes tap2, the packet is divided into two
fragments: fragment A and B, similar to (1520 = 1510 + 10).
When the packet passes tap3, the larger fragment packet A is
divided into two fragments A1 and A2, similar to (1510 = 1500 + 10).
Finally, the bond interface receives three fragments:
A1, A2, and B (1520 = 1500 + 10 + 10).
One fragmented packet A2 is smaller than the minimum Ethernet
frame length, so it needs to be padded.

|---------------------------------------------------|
|                      HOST                         |
| |--------------|   |----------------------------| |
| |      ns2     |   |      |--------------|      | |
| |  |--------|  |   |  |--------|    |--------|  | |
| |  |  tap1  |  |   |  |  tap2  | ns1|  tap3  |  | |
| |  |mtu=1510|  |   |  |mtu=1510|    |mtu=1500|  | |
| |--|1.1.1.1 |--|   |--|1.1.1.2 |----|2.1.1.1 |--| |
|    |--------|         |--------|    |--------|    |
|         |                 |              |        |
|         |-----------------|              |        |
|                                          |        |
|                                      |--------|   |
|                                      |  bond  |   |
|--------------------------------------|mtu=1500|---|
                                       |--------|

When processing the preceding packets above,
DPDK would aggregate fragmented packets A2 and B.
And error packets are generated, which padding(zero)
is displayed in the middle of the packet.

A2 + B:
0000   fa 16 3e 9f fb 82 fa 47 b2 57 dc 20 08 00 45 00
0010   00 33 b4 66 00 ba 3f 01 c1 a5 01 01 01 01 02 01
0020   01 02 c0 c1 c2 c3 c4 c5 c6 c7 00 00 00 00 00 00
0030   00 00 00 00 00 00 00 00 00 00 00 00 c8 c9 ca cb
0040   cc cd ce cf d0 d1 d2 d3 d4 d5 d6 d7 d8 d9 da db
0050   dc dd de df e0 e1 e2 e3 e4 e5 e6

So, we would calculate the length of padding, and remove
the padding in pkt_len and data_len before aggregation.
And also we have the fix for both ipv4 and ipv6.

Fixes: 7f0983ee331c ("ip_frag: check fragment length of incoming packet")
Cc: stable@dpdk.org

Signed-off-by: Yicai Lu <luyicai@huawei.com>
---
v5 -> v6: Have the fix for ipv6.
---
 lib/librte_ip_frag/rte_ipv4_reassembly.c | 11 ++++++++---
 lib/librte_ip_frag/rte_ipv6_reassembly.c |  9 +++++++--
 2 files changed, 15 insertions(+), 5 deletions(-)
  

Comments

Ananyev, Konstantin Dec. 18, 2020, 11:41 a.m. UTC | #1
> 
> In some situations, we would get several ip fragments, which total
> data length is less than min_ip_len(64) and padding with zeros.
> We simulated intermediate fragments by modifying the MTU.
> To illustrate the problem, we simplify the packet format and
> ignore the impact of the packet header.In namespace2,
> a packet whose data length is 1520 is sent.
> When the packet passes tap2, the packet is divided into two
> fragments: fragment A and B, similar to (1520 = 1510 + 10).
> When the packet passes tap3, the larger fragment packet A is
> divided into two fragments A1 and A2, similar to (1510 = 1500 + 10).
> Finally, the bond interface receives three fragments:
> A1, A2, and B (1520 = 1500 + 10 + 10).
> One fragmented packet A2 is smaller than the minimum Ethernet
> frame length, so it needs to be padded.
> 
> |---------------------------------------------------|
> |                      HOST                         |
> | |--------------|   |----------------------------| |
> | |      ns2     |   |      |--------------|      | |
> | |  |--------|  |   |  |--------|    |--------|  | |
> | |  |  tap1  |  |   |  |  tap2  | ns1|  tap3  |  | |
> | |  |mtu=1510|  |   |  |mtu=1510|    |mtu=1500|  | |
> | |--|1.1.1.1 |--|   |--|1.1.1.2 |----|2.1.1.1 |--| |
> |    |--------|         |--------|    |--------|    |
> |         |                 |              |        |
> |         |-----------------|              |        |
> |                                          |        |
> |                                      |--------|   |
> |                                      |  bond  |   |
> |--------------------------------------|mtu=1500|---|
>                                        |--------|
> 
> When processing the preceding packets above,
> DPDK would aggregate fragmented packets A2 and B.
> And error packets are generated, which padding(zero)
> is displayed in the middle of the packet.
> 
> A2 + B:
> 0000   fa 16 3e 9f fb 82 fa 47 b2 57 dc 20 08 00 45 00
> 0010   00 33 b4 66 00 ba 3f 01 c1 a5 01 01 01 01 02 01
> 0020   01 02 c0 c1 c2 c3 c4 c5 c6 c7 00 00 00 00 00 00
> 0030   00 00 00 00 00 00 00 00 00 00 00 00 c8 c9 ca cb
> 0040   cc cd ce cf d0 d1 d2 d3 d4 d5 d6 d7 d8 d9 da db
> 0050   dc dd de df e0 e1 e2 e3 e4 e5 e6
> 
> So, we would calculate the length of padding, and remove
> the padding in pkt_len and data_len before aggregation.
> And also we have the fix for both ipv4 and ipv6.
> 
> Fixes: 7f0983ee331c ("ip_frag: check fragment length of incoming packet")
> Cc: stable@dpdk.org
> 
> Signed-off-by: Yicai Lu <luyicai@huawei.com>
> ---
> v5 -> v6: Have the fix for ipv6.
> ---
>  lib/librte_ip_frag/rte_ipv4_reassembly.c | 11 ++++++++---
>  lib/librte_ip_frag/rte_ipv6_reassembly.c |  9 +++++++--
>  2 files changed, 15 insertions(+), 5 deletions(-)
> 
> diff --git a/lib/librte_ip_frag/rte_ipv4_reassembly.c b/lib/librte_ip_frag/rte_ipv4_reassembly.c
> index 1dda8ac..69666c8 100644
> --- a/lib/librte_ip_frag/rte_ipv4_reassembly.c
> +++ b/lib/librte_ip_frag/rte_ipv4_reassembly.c
> @@ -104,6 +104,7 @@ struct rte_mbuf *
>  	const unaligned_uint64_t *psd;
>  	uint16_t flag_offset, ip_ofs, ip_flag;
>  	int32_t ip_len;
> +	int32_t trim;
> 
>  	flag_offset = rte_be_to_cpu_16(ip_hdr->fragment_offset);
>  	ip_ofs = (uint16_t)(flag_offset & RTE_IPV4_HDR_OFFSET_MASK);
> @@ -117,14 +118,15 @@ struct rte_mbuf *
> 
>  	ip_ofs *= RTE_IPV4_HDR_OFFSET_UNITS;
>  	ip_len = rte_be_to_cpu_16(ip_hdr->total_length) - mb->l3_len;
> +	trim = mb->pkt_len - (ip_len + mb->l3_len + mb->l2_len);
> 
>  	IP_FRAG_LOG(DEBUG, "%s:%d:\n"
> -		"mbuf: %p, tms: %" PRIu64
> -		", key: <%" PRIx64 ", %#x>, ofs: %u, len: %d, flags: %#x\n"
> +		"mbuf: %p, tms: %" PRIu64 ", key: <%" PRIx64 ", %#x>"
> +		"ofs: %u, len: %d, padding: %d, flags: %#x\n"
>  		"tbl: %p, max_cycles: %" PRIu64 ", entry_mask: %#x, "
>  		"max_entries: %u, use_entries: %u\n\n",
>  		__func__, __LINE__,
> -		mb, tms, key.src_dst[0], key.id, ip_ofs, ip_len, ip_flag,
> +		mb, tms, key.src_dst[0], key.id, ip_ofs, ip_len, trim, ip_flag,
>  		tbl, tbl->max_cycles, tbl->entry_mask, tbl->max_entries,
>  		tbl->use_entries);
> 
> @@ -134,6 +136,9 @@ struct rte_mbuf *
>  		return NULL;
>  	}
> 
> +	if (unlikely(trim > 0))
> +		rte_pktmbuf_trim(mb, trim);
> +
>  	/* try to find/add entry into the fragment's table. */
>  	if ((fp = ip_frag_find(tbl, dr, &key, tms)) == NULL) {
>  		IP_FRAG_MBUF2DR(dr, mb);
> diff --git a/lib/librte_ip_frag/rte_ipv6_reassembly.c b/lib/librte_ip_frag/rte_ipv6_reassembly.c
> index ad01055..4037da0 100644
> --- a/lib/librte_ip_frag/rte_ipv6_reassembly.c
> +++ b/lib/librte_ip_frag/rte_ipv6_reassembly.c
> @@ -142,6 +142,7 @@ struct rte_mbuf *
>  	struct ip_frag_key key;
>  	uint16_t ip_ofs;
>  	int32_t ip_len;
> +	int32_t trim;
> 
>  	rte_memcpy(&key.src_dst[0], ip_hdr->src_addr, 16);
>  	rte_memcpy(&key.src_dst[2], ip_hdr->dst_addr, 16);
> @@ -158,16 +159,17 @@ struct rte_mbuf *
>  	 * this is what we remove from the payload len.
>  	 */
>  	ip_len = rte_be_to_cpu_16(ip_hdr->payload_len) - sizeof(*frag_hdr);
> +	trim = mb->pkt_len - (ip_len + mb->l3_len + mb->l2_len);
> 
>  	IP_FRAG_LOG(DEBUG, "%s:%d:\n"
>  		"mbuf: %p, tms: %" PRIu64
>  		", key: <" IPv6_KEY_BYTES_FMT ", %#x>, "
> -		"ofs: %u, len: %d, flags: %#x\n"
> +		"ofs: %u, len: %d, padding: %d, flags: %#x\n"
>  		"tbl: %p, max_cycles: %" PRIu64 ", entry_mask: %#x, "
>  		"max_entries: %u, use_entries: %u\n\n",
>  		__func__, __LINE__,
>  		mb, tms, IPv6_KEY_BYTES(key.src_dst), key.id, ip_ofs, ip_len,
> -		RTE_IPV6_GET_MF(frag_hdr->frag_data),
> +		trim, RTE_IPV6_GET_MF(frag_hdr->frag_data),
>  		tbl, tbl->max_cycles, tbl->entry_mask, tbl->max_entries,
>  		tbl->use_entries);
> 
> @@ -177,6 +179,9 @@ struct rte_mbuf *
>  		return NULL;
>  	}
> 
> +	if (unlikely(trim > 0))
> +		rte_pktmbuf_trim(mb, trim);
> +
>  	/* try to find/add entry into the fragment's table. */
>  	fp = ip_frag_find(tbl, dr, &key, tms);
>  	if (fp == NULL) {
> --

Acked-by: Konstantin Ananyev <konstantin.ananyev@intel.com>

> 1.9.5.msysgit.1
  
Thomas Monjalon Jan. 15, 2021, 10:29 a.m. UTC | #2
> > In some situations, we would get several ip fragments, which total
> > data length is less than min_ip_len(64) and padding with zeros.
> > We simulated intermediate fragments by modifying the MTU.
> > To illustrate the problem, we simplify the packet format and
> > ignore the impact of the packet header.In namespace2,
> > a packet whose data length is 1520 is sent.
> > When the packet passes tap2, the packet is divided into two
> > fragments: fragment A and B, similar to (1520 = 1510 + 10).
> > When the packet passes tap3, the larger fragment packet A is
> > divided into two fragments A1 and A2, similar to (1510 = 1500 + 10).
> > Finally, the bond interface receives three fragments:
> > A1, A2, and B (1520 = 1500 + 10 + 10).
> > One fragmented packet A2 is smaller than the minimum Ethernet
> > frame length, so it needs to be padded.
> > 
> > |---------------------------------------------------|
> > |                      HOST                         |
> > | |--------------|   |----------------------------| |
> > | |      ns2     |   |      |--------------|      | |
> > | |  |--------|  |   |  |--------|    |--------|  | |
> > | |  |  tap1  |  |   |  |  tap2  | ns1|  tap3  |  | |
> > | |  |mtu=1510|  |   |  |mtu=1510|    |mtu=1500|  | |
> > | |--|1.1.1.1 |--|   |--|1.1.1.2 |----|2.1.1.1 |--| |
> > |    |--------|         |--------|    |--------|    |
> > |         |                 |              |        |
> > |         |-----------------|              |        |
> > |                                          |        |
> > |                                      |--------|   |
> > |                                      |  bond  |   |
> > |--------------------------------------|mtu=1500|---|
> >                                        |--------|
> > 
> > When processing the preceding packets above,
> > DPDK would aggregate fragmented packets A2 and B.
> > And error packets are generated, which padding(zero)
> > is displayed in the middle of the packet.
> > 
> > A2 + B:
> > 0000   fa 16 3e 9f fb 82 fa 47 b2 57 dc 20 08 00 45 00
> > 0010   00 33 b4 66 00 ba 3f 01 c1 a5 01 01 01 01 02 01
> > 0020   01 02 c0 c1 c2 c3 c4 c5 c6 c7 00 00 00 00 00 00
> > 0030   00 00 00 00 00 00 00 00 00 00 00 00 c8 c9 ca cb
> > 0040   cc cd ce cf d0 d1 d2 d3 d4 d5 d6 d7 d8 d9 da db
> > 0050   dc dd de df e0 e1 e2 e3 e4 e5 e6
> > 
> > So, we would calculate the length of padding, and remove
> > the padding in pkt_len and data_len before aggregation.
> > And also we have the fix for both ipv4 and ipv6.
> > 
> > Fixes: 7f0983ee331c ("ip_frag: check fragment length of incoming packet")
> > Cc: stable@dpdk.org
> > 
> > Signed-off-by: Yicai Lu <luyicai@huawei.com>
> 
> Acked-by: Konstantin Ananyev <konstantin.ananyev@intel.com>

Applied, thanks
  

Patch

diff --git a/lib/librte_ip_frag/rte_ipv4_reassembly.c b/lib/librte_ip_frag/rte_ipv4_reassembly.c
index 1dda8ac..69666c8 100644
--- a/lib/librte_ip_frag/rte_ipv4_reassembly.c
+++ b/lib/librte_ip_frag/rte_ipv4_reassembly.c
@@ -104,6 +104,7 @@  struct rte_mbuf *
 	const unaligned_uint64_t *psd;
 	uint16_t flag_offset, ip_ofs, ip_flag;
 	int32_t ip_len;
+	int32_t trim;
 
 	flag_offset = rte_be_to_cpu_16(ip_hdr->fragment_offset);
 	ip_ofs = (uint16_t)(flag_offset & RTE_IPV4_HDR_OFFSET_MASK);
@@ -117,14 +118,15 @@  struct rte_mbuf *
 
 	ip_ofs *= RTE_IPV4_HDR_OFFSET_UNITS;
 	ip_len = rte_be_to_cpu_16(ip_hdr->total_length) - mb->l3_len;
+	trim = mb->pkt_len - (ip_len + mb->l3_len + mb->l2_len);
 
 	IP_FRAG_LOG(DEBUG, "%s:%d:\n"
-		"mbuf: %p, tms: %" PRIu64
-		", key: <%" PRIx64 ", %#x>, ofs: %u, len: %d, flags: %#x\n"
+		"mbuf: %p, tms: %" PRIu64 ", key: <%" PRIx64 ", %#x>"
+		"ofs: %u, len: %d, padding: %d, flags: %#x\n"
 		"tbl: %p, max_cycles: %" PRIu64 ", entry_mask: %#x, "
 		"max_entries: %u, use_entries: %u\n\n",
 		__func__, __LINE__,
-		mb, tms, key.src_dst[0], key.id, ip_ofs, ip_len, ip_flag,
+		mb, tms, key.src_dst[0], key.id, ip_ofs, ip_len, trim, ip_flag,
 		tbl, tbl->max_cycles, tbl->entry_mask, tbl->max_entries,
 		tbl->use_entries);
 
@@ -134,6 +136,9 @@  struct rte_mbuf *
 		return NULL;
 	}
 
+	if (unlikely(trim > 0))
+		rte_pktmbuf_trim(mb, trim);
+
 	/* try to find/add entry into the fragment's table. */
 	if ((fp = ip_frag_find(tbl, dr, &key, tms)) == NULL) {
 		IP_FRAG_MBUF2DR(dr, mb);
diff --git a/lib/librte_ip_frag/rte_ipv6_reassembly.c b/lib/librte_ip_frag/rte_ipv6_reassembly.c
index ad01055..4037da0 100644
--- a/lib/librte_ip_frag/rte_ipv6_reassembly.c
+++ b/lib/librte_ip_frag/rte_ipv6_reassembly.c
@@ -142,6 +142,7 @@  struct rte_mbuf *
 	struct ip_frag_key key;
 	uint16_t ip_ofs;
 	int32_t ip_len;
+	int32_t trim;
 
 	rte_memcpy(&key.src_dst[0], ip_hdr->src_addr, 16);
 	rte_memcpy(&key.src_dst[2], ip_hdr->dst_addr, 16);
@@ -158,16 +159,17 @@  struct rte_mbuf *
 	 * this is what we remove from the payload len.
 	 */
 	ip_len = rte_be_to_cpu_16(ip_hdr->payload_len) - sizeof(*frag_hdr);
+	trim = mb->pkt_len - (ip_len + mb->l3_len + mb->l2_len);
 
 	IP_FRAG_LOG(DEBUG, "%s:%d:\n"
 		"mbuf: %p, tms: %" PRIu64
 		", key: <" IPv6_KEY_BYTES_FMT ", %#x>, "
-		"ofs: %u, len: %d, flags: %#x\n"
+		"ofs: %u, len: %d, padding: %d, flags: %#x\n"
 		"tbl: %p, max_cycles: %" PRIu64 ", entry_mask: %#x, "
 		"max_entries: %u, use_entries: %u\n\n",
 		__func__, __LINE__,
 		mb, tms, IPv6_KEY_BYTES(key.src_dst), key.id, ip_ofs, ip_len,
-		RTE_IPV6_GET_MF(frag_hdr->frag_data),
+		trim, RTE_IPV6_GET_MF(frag_hdr->frag_data),
 		tbl, tbl->max_cycles, tbl->entry_mask, tbl->max_entries,
 		tbl->use_entries);
 
@@ -177,6 +179,9 @@  struct rte_mbuf *
 		return NULL;
 	}
 
+	if (unlikely(trim > 0))
+		rte_pktmbuf_trim(mb, trim);
+
 	/* try to find/add entry into the fragment's table. */
 	fp = ip_frag_find(tbl, dr, &key, tms);
 	if (fp == NULL) {